74 lines
1.9 KiB
SQL
74 lines
1.9 KiB
SQL
-- 修复课件时长数据
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-- 执行日期：2025-12-05
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-- 问题：部分课件的duration字段为0或null，导致进度计算不准确
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USE ry_study;
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-- 1. 查看当前课程1的所有课件时长情况
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SELECT
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id,
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name,
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type,
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duration,
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file_path
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FROM courseware
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WHERE course_id = 1
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ORDER BY id;
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-- 2. 根据学习详情中的最大播放位置，推算视频的实际时长并更新
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-- （如果有学生播放到末尾，最大videoPosition可以作为duration的参考）
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UPDATE courseware c
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SET c.duration = (
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SELECT MAX(ld.video_end_position) + 3 -- 加3秒作为缓冲
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FROM learning_detail ld
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WHERE ld.courseware_id = c.id
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AND ld.video_end_position > 0
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)
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WHERE c.type = 'video'
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AND c.course_id = 1
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AND (c.duration IS NULL OR c.duration = 0)
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AND EXISTS (
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SELECT 1 FROM learning_detail ld2
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WHERE ld2.courseware_id = c.id
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AND ld2.video_end_position > 0
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);
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-- 3. 手动设置已知的课件时长（根据日志）
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-- 课件873：实际17秒，当前配置30秒
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UPDATE courseware
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SET duration = 17
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WHERE id = 873 AND course_id = 1;
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-- 课件882：实际3秒，当前配置0
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UPDATE courseware
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SET duration = 3
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WHERE id = 882 AND course_id = 1;
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-- 4. 验证修复结果
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SELECT
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id,
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name,
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type,
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duration,
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CASE
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WHEN duration IS NULL THEN '⚠️ NULL'
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WHEN duration = 0 THEN '⚠️ 0'
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ELSE '✅ 正常'
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END as status
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FROM courseware
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WHERE course_id = 1
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ORDER BY id;
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-- 5. 检查学习详情中的最大播放位置（可以作为duration的参考）
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SELECT
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c.id as courseware_id,
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c.name,
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c.duration as configured_duration,
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MAX(ld.video_end_position) as max_position,
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COUNT(ld.id) as record_count
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FROM courseware c
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LEFT JOIN learning_detail ld ON ld.courseware_id = c.id
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WHERE c.course_id = 1 AND c.type = 'video'
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GROUP BY c.id, c.name, c.duration
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ORDER BY c.id;
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