168 lines
4.6 KiB
SQL
168 lines
4.6 KiB
SQL
-- 🔍 紧急诊断 - 日历数据不一致问题
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-- 日期: 2026-01-24
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-- 问题: 重新编译后，日历还是只显示6个订单
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-- ============================================
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-- SQL 1: 检查用户ID=1的所有订单状态分布
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-- ============================================
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SELECT
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status,
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CASE status
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WHEN 0 THEN '待支付'
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WHEN 1 THEN '待接单/已支付'
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WHEN 2 THEN '待服务/已接单'
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WHEN 3 THEN '服务中'
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WHEN 4 THEN '已完成'
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WHEN -1 THEN '已取消'
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ELSE '其他'
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END AS status_text,
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COUNT(*) AS count
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FROM `order`
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WHERE user_id = 1
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AND deleted = 0
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GROUP BY status
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ORDER BY status;
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-- ============================================
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-- SQL 2: 检查待服务订单（status=1或2）的详细信息
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-- ============================================
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SELECT
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id,
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order_no,
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status,
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CASE status
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WHEN 1 THEN '待接单'
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WHEN 2 THEN '待服务'
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ELSE '其他'
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END AS status_text,
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service_date,
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time_slot,
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service_name,
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create_time
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FROM `order`
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WHERE user_id = 1
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AND status IN (1, 2)
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AND deleted = 0
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ORDER BY service_date, create_time;
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-- ============================================
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-- SQL 3: 检查2026年1月的订单（日历当前显示的）
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-- ============================================
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SELECT
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id,
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order_no,
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status,
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CASE status
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WHEN 0 THEN '待支付'
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WHEN 1 THEN '待接单'
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WHEN 2 THEN '待服务'
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WHEN 3 THEN '服务中'
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WHEN 4 THEN '已完成'
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ELSE '其他'
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END AS status_text,
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service_date,
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time_slot,
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service_name
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FROM `order`
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WHERE user_id = 1
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AND deleted = 0
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AND service_date >= '2026-01-01'
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AND service_date <= '2026-01-31'
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ORDER BY service_date, time_slot;
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-- ============================================
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-- SQL 4: 检查"我的预约"页面可能使用的查询
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-- ============================================
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-- 预约页面可能查询status=1或2的订单
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SELECT
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COUNT(*) AS total_count,
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SUM(CASE WHEN status = 1 THEN 1 ELSE 0 END) AS status_1_count,
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SUM(CASE WHEN status = 2 THEN 1 ELSE 0 END) AS status_2_count
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FROM `order`
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WHERE user_id = 1
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AND status IN (1, 2)
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AND deleted = 0;
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-- ============================================
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-- SQL 5: 检查所有订单的service_date分布
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-- ============================================
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SELECT
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CASE
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WHEN service_date IS NULL THEN '日期为空'
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WHEN service_date >= '2026-01-01' AND service_date <= '2026-01-31' THEN '2026年1月'
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WHEN service_date >= '2026-02-01' AND service_date <= '2026-02-29' THEN '2026年2月'
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WHEN service_date >= '2026-03-01' AND service_date <= '2026-03-31' THEN '2026年3月'
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WHEN service_date < '2026-01-01' THEN '2026年1月之前'
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ELSE '2026年3月之后'
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END AS date_range,
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COUNT(*) AS count
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FROM `order`
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WHERE user_id = 1
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AND deleted = 0
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GROUP BY date_range
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ORDER BY date_range;
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-- ============================================
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-- SQL 6: 检查日历API实际会查询到的数据
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-- ============================================
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-- 模拟 getAllAppointments 接口的查询
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SELECT
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id,
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order_no,
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status,
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service_date,
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time_slot,
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service_name,
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CASE status
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WHEN 1 THEN '待接单'
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WHEN 2 THEN '待服务'
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WHEN 3 THEN '服务中'
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WHEN 4 THEN '已完成'
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ELSE '其他'
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END AS status_text
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FROM `order`
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WHERE user_id = 1
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AND status IN (1, 2, 3, 4)
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AND deleted = 0
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ORDER BY service_date, time_slot;
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-- ============================================
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-- SQL 7: 检查是否有其他用户ID的订单
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-- ============================================
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SELECT
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user_id,
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COUNT(*) AS order_count,
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SUM(CASE WHEN status IN (1, 2) THEN 1 ELSE 0 END) AS pending_count
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FROM `order`
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WHERE deleted = 0
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GROUP BY user_id
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ORDER BY order_count DESC
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LIMIT 10;
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-- ============================================
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-- 执行说明
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-- ============================================
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/*
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请在Navicat中依次执行上面的SQL，重点关注：
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1. SQL 1: 查看订单状态分布
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- 如果status=1或2的订单不是62个，说明预约页面的查询条件不同
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2. SQL 2: 查看待服务订单详情
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- 确认这些订单的service_date是否为空或在不同月份
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3. SQL 4: 统计待服务订单数量
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- 确认是否真的有62个待服务订单
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4. SQL 6: 模拟日历API查询
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- 这个查询结果应该和日历"全部订单"视图显示的一致
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5. SQL 7: 检查用户ID
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- 确认订单是否都属于user_id=1
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执行完成后，请告诉我：
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- SQL 1的结果：各状态有多少订单
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- SQL 4的结果：待服务订单总数
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- SQL 6的结果：返回了多少条记录
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*/
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