100 lines
2.3 KiB
SQL
100 lines
2.3 KiB
SQL
-- ==================== 检查学生数据 ====================
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-- 1. 检查student表中是否有数据
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SELECT
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id,
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user_id,
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student_name,
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gender,
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birth_date,
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grade,
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school,
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deleted,
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create_time
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FROM student
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ORDER BY id
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LIMIT 20;
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-- 2. 检查是否有deleted=0的学生
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SELECT COUNT(*) as total_students
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FROM student
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WHERE deleted = 0;
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-- 3. 检查user_id=1对应的学生
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SELECT
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id,
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user_id,
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student_name,
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gender,
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deleted
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FROM student
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WHERE user_id = 1;
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-- 4. 如果没有学生数据,插入测试学生
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INSERT INTO student (
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user_id,
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student_name,
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gender,
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birth_date,
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grade,
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school,
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class_name,
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parent_name,
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parent_phone,
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parent_relation,
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learning_status,
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status,
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deleted,
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tenant_id,
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create_time,
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update_time
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) VALUES (
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1, -- user_id (家长ID)
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'小明', -- student_name
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1, -- gender (1=男)
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'2015-05-15', -- birth_date
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'小学三年级', -- grade
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'实验小学', -- school
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'三年级1班', -- class_name
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'张女士', -- parent_name
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'13800000001', -- parent_phone
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'母亲', -- parent_relation
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'学习状态良好', -- learning_status
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1, -- status (1=正常)
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0, -- deleted (0=未删除)
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1, -- tenant_id
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NOW(), -- create_time
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NOW() -- update_time
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);
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-- 5. 验证插入结果
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SELECT
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id,
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user_id,
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student_name,
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gender,
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birth_date,
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grade,
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deleted
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FROM student
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WHERE user_id = 1;
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-- 6. 更新成长记录的student_id
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-- 如果成长记录中的student_id不正确,需要更新
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UPDATE growth_record
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SET student_id = (SELECT id FROM student WHERE user_id = 1 LIMIT 1)
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WHERE student_id = 1
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AND NOT EXISTS (SELECT 1 FROM student WHERE id = 1);
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-- 7. 验证成长记录
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SELECT
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gr.id,
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gr.student_id,
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gr.student_name,
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s.id as actual_student_id,
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s.student_name as actual_student_name
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FROM growth_record gr
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LEFT JOIN student s ON gr.student_id = s.id
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WHERE gr.deleted = 0
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LIMIT 10;
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