192 lines
4.5 KiB
SQL
192 lines
4.5 KiB
SQL
-- 验证陪伴员待接单查询逻辑
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-- 目的：检查派单后陪伴员是否能正确查询到待接单订单
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-- ========================================
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-- 陪伴员待接单查询逻辑（后端实现）
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-- ========================================
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-- 查询条件：
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-- 1. teacher_id = 当前陪伴员ID
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-- 2. status = 1（待接单）
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-- 3. pay_status = 1（已支付）
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-- 4. deleted = 0（未删除）
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-- ========================================
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-- 1. 查看最近派单的订单（订单306）
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SELECT
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id,
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order_no,
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teacher_id,
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status,
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CASE
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WHEN status = 0 THEN '待派单'
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WHEN status = 1 THEN '待接单'
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WHEN status = 2 THEN '待服务'
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WHEN status = 3 THEN '服务中'
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WHEN status = 4 THEN '已完成'
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WHEN status = 5 THEN '已取消'
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ELSE CONCAT('未知(', status, ')')
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END as status_name,
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pay_status,
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CASE
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WHEN pay_status = 0 THEN '未支付'
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WHEN pay_status = 1 THEN '已支付'
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WHEN pay_status = 2 THEN '已退款'
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ELSE CONCAT('未知(', pay_status, ')')
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END as pay_status_name,
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deleted,
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create_time,
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update_time
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FROM `order`
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WHERE id = 306;
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-- 2. 查看陪伴员10096的所有待接单订单（模拟后端查询）
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SELECT
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id,
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order_no,
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teacher_id,
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status,
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pay_status,
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service_date,
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time_slot,
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service_address,
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pay_amount,
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create_time
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FROM `order`
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WHERE teacher_id = 10096
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AND status = 1
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AND pay_status = 1
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AND deleted = 0
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ORDER BY create_time DESC;
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-- 3. 统计陪伴员10096的待接单数量
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SELECT
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COUNT(*) as pending_count
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FROM `order`
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WHERE teacher_id = 10096
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AND status = 1
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AND pay_status = 1
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AND deleted = 0;
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-- 4. 查看所有陪伴员的待接单订单分布
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SELECT
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teacher_id,
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COUNT(*) as pending_count,
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GROUP_CONCAT(id ORDER BY id) as order_ids
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FROM `order`
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WHERE status = 1
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AND pay_status = 1
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AND deleted = 0
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GROUP BY teacher_id
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ORDER BY pending_count DESC;
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-- 5. 检查是否有订单状态不一致的情况
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-- （已派单但status不是1，或未派单但status是1）
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SELECT
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'已派单但status不是1' as issue_type,
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id,
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order_no,
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teacher_id,
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status,
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pay_status,
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create_time
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FROM `order`
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WHERE teacher_id IS NOT NULL
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AND status != 1
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AND status != 2
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AND status != 3
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AND status != 4
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AND status != 5
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AND pay_status = 1
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AND deleted = 0
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LIMIT 10;
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-- 6. 检查teacher表中的user_id映射关系
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-- （确认陪伴员的userId和teacherId是否正确关联）
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SELECT
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t.id as teacher_id,
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t.user_id,
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t.teacher_name,
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t.real_name,
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t.phone,
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u.id as user_table_id,
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u.nickname,
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u.phone as user_phone
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FROM teacher t
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LEFT JOIN user u ON t.user_id = u.id
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WHERE t.id = 10096;
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-- 7. 查看订单306的完整信息（包括学生和家长信息）
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SELECT
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o.id,
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o.order_no,
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o.teacher_id,
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o.status,
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o.pay_status,
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o.user_id,
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o.student_id,
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o.service_name,
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o.service_date,
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o.time_slot,
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o.service_address,
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o.pay_amount,
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o.user_remark,
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u.nickname as parent_name,
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u.phone as parent_phone,
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s.name as student_name,
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s.grade as student_grade,
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s.age as student_age
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FROM `order` o
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LEFT JOIN user u ON o.user_id = u.id
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LEFT JOIN student s ON o.student_id = s.id
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WHERE o.id = 306;
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-- 8. 检查是否有重复的teacher_id（可能导致查询混乱）
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SELECT
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teacher_id,
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COUNT(*) as count
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FROM `order`
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WHERE teacher_id IS NOT NULL
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AND deleted = 0
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GROUP BY teacher_id
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HAVING count > 1
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ORDER BY count DESC
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LIMIT 10;
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-- 9. 查看最近10条派单记录（检查派单后的状态变化）
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SELECT
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id,
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order_no,
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teacher_id,
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status,
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CASE
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WHEN status = 0 THEN '待派单'
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WHEN status = 1 THEN '待接单'
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WHEN status = 2 THEN '待服务'
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WHEN status = 3 THEN '服务中'
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WHEN status = 4 THEN '已完成'
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WHEN status = 5 THEN '已取消'
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ELSE CONCAT('未知(', status, ')')
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END as status_name,
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pay_status,
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create_time,
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update_time
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FROM `order`
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WHERE teacher_id IS NOT NULL
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AND deleted = 0
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ORDER BY update_time DESC
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LIMIT 10;
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-- 10. 检查订单306的历史状态变化（如果有日志表）
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-- 注意：这个查询假设有order_log表，如果没有则跳过
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-- SELECT
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-- order_id,
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-- old_status,
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-- new_status,
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-- old_teacher_id,
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-- new_teacher_id,
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-- create_time,
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-- operator
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-- FROM order_log
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-- WHERE order_id = 306
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-- ORDER BY create_time DESC;
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