-- ============================================
-- 多身份功能 - 数据库脚本
-- 创建时间：2026-02-28
-- 功能：创建 user_roles 表，支持一个账号多个角色
-- ============================================

-- 1. 创建 user_roles 表
CREATE TABLE IF NOT EXISTS `user_roles` (
  `id` BIGINT AUTO_INCREMENT PRIMARY KEY COMMENT '主键ID',
  `user_id` BIGINT NOT NULL COMMENT '用户ID',
  `role_type` VARCHAR(50) NOT NULL COMMENT '角色类型：teacher/manager/distributor/provider/parent',
  `is_primary` TINYINT DEFAULT 0 COMMENT '是否主身份：0=否，1=是',
  `status` TINYINT DEFAULT 1 COMMENT '状态：0=禁用，1=启用',
  `create_time` DATETIME DEFAULT CURRENT_TIMESTAMP COMMENT '创建时间',
  `update_time` DATETIME DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP COMMENT '更新时间',
  INDEX `idx_user_id` (`user_id`),
  INDEX `idx_role_type` (`role_type`),
  UNIQUE KEY `uk_user_role` (`user_id`, `role_type`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COMMENT='用户角色关联表';

-- 2. 初始化数据：将现有用户的主身份同步到 user_roles 表
INSERT INTO `user_roles` (`user_id`, `role_type`, `is_primary`, `status`)
SELECT 
  `id` as user_id,
  `role` as role_type,
  1 as is_primary,
  1 as status
FROM `user`
WHERE `role` IS NOT NULL AND `role` != ''
ON DUPLICATE KEY UPDATE `is_primary` = 1;

-- 3. 验证数据
SELECT 
  '数据同步完成' as message,
  COUNT(*) as total_users,
  COUNT(DISTINCT user_id) as users_with_roles
FROM user_roles;

-- 4. 查看前10条数据
SELECT 
  u.id,
  u.phone,
  u.role as primary_role,
  GROUP_CONCAT(ur.role_type) as all_roles,
  GROUP_CONCAT(IF(ur.is_primary = 1, '✓', '')) as primary_mark
FROM user u
LEFT JOIN user_roles ur ON u.id = ur.user_id
GROUP BY u.id
LIMIT 10;